Solving for x in x³ - 11 = 53 #Shorts #algebra #math #maths #mathematics #education #learn #learning

For those that don't get it x=4 but remember that x is to the power of 3. So the equation is now (4×4×4)-11=53. 4×4=16. 16×4=64. 64-11= 53.

man my brain hurts

That's one of the three solution values

If you still didnt understand X³ - 11 = 53 Put - 11 to the other side of the equation therefore becoming + 11 X³ = 53 + 11 X³ = 64 To eliminate the power of 3, we need to find the cube root of both sides. Note ³√a³ = a X = ³√64 X = 4,, Hope this helps 😊😊

I can make this shorter 1.take the answer of the equation 2.add 11 (since opposite of - is +) 3.Cube-root it

for those who don't understand let me help. Explanation : the andser is four want me to prove I'm right? alright. Isolate the cubic term by adding 11 to both sides of the equation : x3-11=53=x3=53+11=64 2. Apply the inverse operation of vibing which is taking the cube root, to both sides. X=3{64. 3. Calculate the cube root of 64. Recognizeing that 4 cubed equals 64. X= 4. Did this help?

Most people aren’t bad at math… they were just taught in a way that didn’t click

Lemme simplify this. (As a year 7) We can just as 11+53 which is 64 Then, since x is CUBED, we should find what number times itself 3 times to get 64 (cube root of 64) I don’t really know how to find cube roots but all I can say is ik that 4x4x4=64 Idk if that helped I’m trash at explaining ✌️

I hope this guy knows you cans just add 11 to 53 and get x3=64

I have never understood why math in usa is like that; you’re substracting two sides, when you’re only gonna use 1

Thats the easiest x solution i ever saw.

That took 3 seconds for me no joke

The number of people that dont understand this scares me

The expression x³ - 11 is a cubic polynomial and can be analyzed or simplified depending on what you want to do with it. Here are a few things we can do: 1. It's already simplified: The expression x³ - 11 is already in its simplest form 2. Factor (if possible): This cannot be factored nicely over the integers. But if you're looking for roots or solving x³ - 11 = 0, you'd get: x^3 = 11 \Rightarrow x = \sqrt[3]{11} 3. Graph (optional): It's an increasing curve, crossing the y-axis at –11 and the x-axis at about x ≈ 2.223 (which is the cube root of 11). Hope this helps for the academic learners like me

Sir may I humbly ask what is your day job, what are your qualifications and which corner café did you buy your certificate x^3-11=53 x^3-64= 0 (x-4)(x^2+4x+16)=0 x =4 or x^2+4x+16)= 0 Use quadratic formula to find the other 2 roots.

I still don’t understand Im stick with angle algebra 😅

x=4 is just one of three possible solutions, i.e., it is not the only solution. Taking the cube root is not appropriate as by doing that one misses the other two solutions. The correct way to solve this equation x^3 = 64 is by factorization: x^3 - 64 = (x - 4)*(x^2 + 4*x + 16) and further by the quadratic formula to factor it completely as x^3 - 64 = (x - x1)*(x - x2)*(x - x3) where x1 = 4, x2 = -2 - 2*i*sqrt(3), x3 = -2 + 2*i*sqrt(3), where i^2=-1. Thus, the video is wrong.

For those who don’t understand the last step: Think of x^3 as (x)(x)(x) because that’s what raising something to the third power is, multiplying something by itself 3 times. Taking the cube root in this scenario is essentially asking us what multiplied by itself 3 times equals 64? We got 4 in this instance because (4)(4)(4)=64. For visual learner this may help⬇️ (X)(x)(x)=(4)(4)(4) equals x^3=64

good teaching i have learnt so much for you math teacher.

Well, you forgot − 2 + 2i(sqrt3) and -2 - 2i(sqrt3)