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Comments 16
juancarlos.rolón:
Plug in numbers method never fails
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Plug in numbers method never fails
b²+b-12=0 (b+4)(b-3)=0 b=3, b=-4
I was thinking about it for a minute but I got -4=b using my head and plugging in numbers
3x3=9 9+3=12 B=3
B=3
So, it's just 3 right?
Just a little cuestión, do you know what a aecond degree operation is? 😂😂
The craziest thing is that b=3 is only possible if we do (bxb) first and then add the other b. But if we do (b+b) first, if doesn't do 12. So, should we make it clear by using parenthesis?
3x3+3 is 12
This is an excellent question about hubris. I forgot PEMDAS and went 2b^2=12 with b=+/-square root 6.
Nice to show the math but I was able to figure that answer out in my head while eating spaghetti in about 5 seconds
Does no one in the comments know how to factor in their heads?? Like I get plugging in works fine but factoring it really isn’t that hard and it’s faster to factor in your head than go through a bunch of numbers to plug in
Yo gotta leave them b’s alone THEY TROUBLE man
I'm A kid and now I'm scared I'll be a barely passing guy when I reach this typa formulas.
Its b = 3 and b= -4. Just b = 3 means your answer isnt complete = you are wrong.
Dude... could you uh... make it a little simpler next time? Please? Im not this smart