I did it a slightly different way. Instead of adding and subtracting x^3 + x^2 + x, I only added and subtracted x^3. So x^5 + x^4 + 1 = x^5 + x^4 + x^3 + 1 - x^3 = (x^5 + x^4 + x^3) - (x^3 - 1) = x^3(x^2 + x + 1) - (x - 1)(x^2 + x + 1) = (x^3 - x + 1)(x^2 + x + 1).
advika_tara1 month, 3 weeks ago
indeed satisfying
J
jilllewis3301 month, 3 weeks ago
I love complex world
abigailbrown4821 month, 2 weeks ago
The marker switch is so smooth
R
raagini_dhar1 month, 3 weeks ago
Try x^6+x^5+x^2
L
lilia_medrano1 month, 3 weeks ago
you are the GOAT!!
V
victoria_elliott1 month, 3 weeks ago
Great, thanks.
advaithsoni6541 month, 3 weeks ago
Really really really cunning and nice!!!!!
G
garry.hayes1 month, 3 weeks ago
Factor theorem my beloved
L
leon.mohaupt1 month, 3 weeks ago
Symbolab says cannot factor further
S
saanvi.sha1 month, 3 weeks ago
ω
olivierdrift981 month, 2 weeks ago
ahh yes, another wild sighting of adding zero to an equation
ekani_goswami1 month, 2 weeks ago
Just factor it in Z mod 3 😂
D
diane_thompson1 month, 3 weeks ago
Hey I have been watching you for a long time now , I'm just curious about where did you study or pursue your mathematical education?
pedrolucas.abreu1 month, 3 weeks ago
cool
advaithsoni6541 month, 3 weeks ago
What is the cubic equation??
C
carrie.chambers1 month, 3 weeks ago
Is it naive to think that x^a+x^b+1 where a,b are non-negative integers, there exists a factorization that is not just 1 * (x^a+x^b+1)
B
beth_burton1 month, 2 weeks ago
Notice that 5, 4 and 0 (from 1=x⁰) form a complete residue class mod 3, so it's divisible by x²+x+1
you're currently carrying my math grade
i feel so satisfied
I did it a slightly different way. Instead of adding and subtracting x^3 + x^2 + x, I only added and subtracted x^3. So x^5 + x^4 + 1 = x^5 + x^4 + x^3 + 1 - x^3 = (x^5 + x^4 + x^3) - (x^3 - 1) = x^3(x^2 + x + 1) - (x - 1)(x^2 + x + 1) = (x^3 - x + 1)(x^2 + x + 1).
indeed satisfying
I love complex world
The marker switch is so smooth
Try x^6+x^5+x^2
you are the GOAT!!
Great, thanks.
Really really really cunning and nice!!!!!
Factor theorem my beloved
Symbolab says cannot factor further
ω
ahh yes, another wild sighting of adding zero to an equation
Just factor it in Z mod 3 😂
Hey I have been watching you for a long time now , I'm just curious about where did you study or pursue your mathematical education?
cool
What is the cubic equation??
Is it naive to think that x^a+x^b+1 where a,b are non-negative integers, there exists a factorization that is not just 1 * (x^a+x^b+1)
Notice that 5, 4 and 0 (from 1=x⁰) form a complete residue class mod 3, so it's divisible by x²+x+1